-3m^2+5m-7=m^2-3m-7

Solution for -3m^2+5m-7=m^2-3m-7 equation:

-3m^2+5m-7=m^2-3m-7

We move all terms to the left:

-3m^2+5m-7-(m^2-3m-7)=0

We get rid of parentheses

-3m^2-m^2+5m+3m+7-7=0

We add all the numbers together, and all the variables

-4m^2+8m=0

a = -4; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-4)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-4}=\frac{-16}{-8}
=+2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-4}=\frac{0}{-8}
=0
$